What are control rods in a nuclear reactor?

$A$ fission reaction is given by ${ }_{92}^{236} U \rightarrow{ }_{54}^{140} Xe +{ }_{38}^{94} Sr + x + y$,where $x$ and $y$ are two particles. Considering ${ }_{92}^{236} U$ to be at rest,the kinetic energies of the products are denoted by $K_{Xe}, K_{Sr}, K_x (2 \ MeV)$ and $K_y (2 \ MeV)$,respectively. Let the binding energies per nucleon of ${ }_{92}^{236} U, { }_{54}^{140} Xe$ and ${ }_{38}^{94} Sr$ be $7.5 \ MeV, 8.5 \ MeV$ and $8.5 \ MeV$ respectively. Considering different conservation laws,the correct option$(s)$ is(are):

One of the fusion reactions in the sun is given by ${ }_{1}^{2} H+{ }_{1}^{1} H \rightarrow{ }_{2}^{3} He+\gamma+Q$. Calculate the energy $Q$ released in the reaction. (in $MeV$)

During the nuclear fusion reaction,

The graph of binding energy per nucleon $(BE/A)$ versus mass number $(A)$ is shown in the figure. Which of the following options is correct?

Energy released in the fission of a single $_{92}U^{235}$ nucleus is $200 \, MeV$. The fission rate of a $_{92}U^{235}$ fuelled reactor operating at a power level of $5 \, W$ is